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-7x^2+6x+1=0
a = -7; b = 6; c = +1;
Δ = b2-4ac
Δ = 62-4·(-7)·1
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-8}{2*-7}=\frac{-14}{-14} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+8}{2*-7}=\frac{2}{-14} =-1/7 $
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